Nicolas FRANCOIS
2010-05-14 00:25:28 UTC
Hi.
Is there any way to obtain the decomposition in simple elements (don't
know exactly how to say this in english) of a fraction of the form :
1
-------------------
(1-X)(1-X^2)(1-X^5)
(to obtain its formal series equivalent \sum a_nX^n, a_n being the
number of ways to pay n€ using 1, 2 and 5€ corners (no, there
is no such thing as a 5€ corner, but there's a 5€ banknote !)).
I'd like to obtain the C-decomposition, what do I have to do ?
More precisely : is there a way to force the use of an extension of
Q(X), by adding roots like exp(2*I*PI/5) or sqrt(2) ?
\bye
PS : clearly I'm not very good at using Axiom documentation !
Is there any way to obtain the decomposition in simple elements (don't
know exactly how to say this in english) of a fraction of the form :
1
-------------------
(1-X)(1-X^2)(1-X^5)
(to obtain its formal series equivalent \sum a_nX^n, a_n being the
number of ways to pay n€ using 1, 2 and 5€ corners (no, there
is no such thing as a 5€ corner, but there's a 5€ banknote !)).
I'd like to obtain the C-decomposition, what do I have to do ?
More precisely : is there a way to force the use of an extension of
Q(X), by adding roots like exp(2*I*PI/5) or sqrt(2) ?
\bye
PS : clearly I'm not very good at using Axiom documentation !
--
Nicolas FRANCOIS | /\
http://nicolas.francois.free.fr | |__|
X--/\\
We are the Micro$oft. _\_V
Resistance is futile.
You will be assimilated. darthvader penguin
Nicolas FRANCOIS | /\
http://nicolas.francois.free.fr | |__|
X--/\\
We are the Micro$oft. _\_V
Resistance is futile.
You will be assimilated. darthvader penguin